20=-5t^2+10

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Solution for 20=-5t^2+10 equation: 



20=-5t^2+10

We move all terms to the left:

20-(-5t^2+10)=0

We get rid of parentheses

5t^2-10+20=0

We add all the numbers together, and all the variables

5t^2+10=0

a = 5; b = 0; c = +10;
Δ = b2-4ac
Δ = 02-4·5·10
Δ = -200
Delta is less than zero, so there is no solution for the equation

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